The resistance R = (V)/(I) , where V = (50 ± 2)V and I = (20 ± 0 . 2)A . The percentage error in R is x % . The value of x to the nearest integer is ________.

Correct answer: 0 ( )/(R) × 100 = ( )/(V) × 100 + ( )/(I) × 100 % error in R = (2)/(50) × 100 + (0 . 2)/(20) × 100 % error in R = 4 + 1 % error in R = 5 %

JEE Main 202116 MarchMorning Shift

Exam: JEE Main
Year: 2021
Date: 16 March
Shift: Morning Shift
Subject: Physics
Chapter: Mathematics in Physics

JEE Main 2021 · 16 March · Morning Shift · Physics · Mathematics in Physics

The resistance R = (V)/(I) , where V = (50 ± 2)V and I = (20 ± 0 ....

The resistance

R = \dfrac{V}{I}

, where

V = \left(50 \pm 2\right)V and

I = \left(20 \pm 0 . 2\right)A

. The percentage error in

is

x %

. The value of

x$ to the nearest integer is ________.

Correct answer

Step-by-step solution

$\dfrac{\DeltaR}{R} \times 100 = \dfrac{\DeltaV}{V} \times 100 + \dfrac{\DeltaI}{I} \times 100$

$%$ error in $R = \dfrac{2}{50} \times 100 + \dfrac{0 . 2}{20} \times 100$

$%$ error in $R = 4 + 1$

$%$ error in $R = 5 %$

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