The density of a solid metal sphere is diameter. The maximum error...

$ρ = \dfrac{m}{\dfrac{4}{3}\pi{\left(\dfrac{d}{2}\right)}^{3}}$

$ρ = \dfrac{6m}{\pi{d}^{3}}$

taking log

$ℓnρ = ℓnm - 3ℓnd$

Maximum error by differentiation

$\dfrac{dρ}{ρ} = \dfrac{dm}{m} + 3\dfrac{dd}{d}$

$\dfrac{dp}{ρ} = 6 + 3 \times 1 . 5$

$= 10 . 5$

Ans. $x = 1050$