JEE Main201911 Jan 2019Evening ShiftPhysicsMathematics in PhysicsActual
A particle moves from the point (2.0 i +4.0 j ) m , at t =0 , with an initial velocity (5.0 i +4.0 j ) ms ⁻¹ . It is acted upon by a constant force which produces a constant acceleration (4.0 i +4.0 j ) ms ⁻² . What is the distance of the particle from the origin at time 2 ~s ?
Options
- A15 ~m
- B20 2 ~m
- C5 ~m
- D10 2 ~m
Correct answer
B. 20 2 ~m
Step-by-step solution
As S = ut + 1 2 a t ² S =(5 i +4 j ) 2+ 1 2 (4 i +4 j ) 4=10 i +8 j +8 i +8 j r _ f - r _ i =18 i +16 j [ as s = . change in position .= r _ f - r _ i ] r _ r =20 i +20 j | r _ r |=20 2