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JEE Main 20172 April
Exam
JEE Main
Year
2017
Date
2 April
Subject
Physics
Chapter
Mathematics in Physics

JEE Main 2017 · 2 April · Physics · Mathematics in Physics

The following observations were taken for determining surface...

The following observations were taken for determining surface tension TT of water by capillary method:

diameter of capillary, D=1.25×10−2mD = 1.25 \times {10}^{- 2}m

rise of water, h=1.45×10−2mh = 1.45 \times {10}^{- 2}m

Using g=9.80ms−2g = 9.80m{s}^{- 2} and the simplified relation T=rhg2×103Nm−1T = \dfrac{rhg}{2} \times {10}^{3}N{m}^{- 1} the possible error in surface tension is closest to:

Options

  1. A1010 %
  2. B0.150 . 15 %
  3. C1.51 . 5 %
  4. D2.42 . 4 %

Correct answer

C. 1.51 . 5 %

Step-by-step solution

Percentage error in surface tension

∆TT=∆rr+∆hh\dfrac{∆ T}{T} = \dfrac{∆ r}{r} + \dfrac{∆ h}{h}

∆rr=∆DD=0.011.25\dfrac{∆ r}{r} = \dfrac{∆ D}{D} = \dfrac{0.01}{1 .25}

∆hh=0.011.45\dfrac{∆ h}{h} = \dfrac{0.01}{1.45}

∴∴ %errorinT = \dfrac{∆ T}{T} \times 100 = \left[\dfrac{0.01}{1.25} + \dfrac{0.01}{1.45}\right] \times 100 = 1.489 \approx 1.5
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