- Exam
- JEE Main
- Year
- 2015
- Date
- 11 April
- Mode
- Online
- Subject
- Physics
- Chapter
- Mathematics in Physics
JEE Main 2015 · 11 April · Online · Physics · Mathematics in Physics
A vector → A is rotated by a small angle ∆ θ radians (∆ θ ≪ 1) to...
Options
- A
- B
- C
- D
Correct answer
C.
Step-by-step solution
\left|\overset{\to}{B} - \overset{\to}{A}\right| = \sqrt{{\left|\overset{\to}{A}\right|}^{2} + {\left|\overset{\to}{A}\right|}^{2} + 2\left|\overset{\to}{A}\right|\left|\overset{\to}{A}\right|\cos \left(180 ° - ∆ \theta\right)}= \sqrt{{\left|\overset{\to}{A}\right|}^{2} + {\left|\overset{\to}{A}\right|}^{2} - 2{\left|\overset{\to}{A}\right|}^{2}cos ∆ \theta}= \sqrt{2{\left|\overset{\to}{A}\right|}^{2} - 2{\left|\overset{\to}{A}\right|}^{2}cos ∆ \theta}= \sqrt{2{\left|\overset{\to}{A}\right|}^{2}\left(1 - cos ∆ \theta\right)}∵ 1 - cos ∆ \theta = 2\sin^{2}\left(\dfrac{∆ \theta}{2}\right)= \sqrt{2{\left|\overset{\to}{A}\right|}^{2} \times 2\sin^{2}\left(\dfrac{∆ \theta}{2}\right)}= 2\left|\overset{\to}{A}\right|\sin \left(\dfrac{∆ \theta}{2}\right)∆ \theta, \sin \left(\dfrac{∆ \theta}{2}\right) ≃ \left(\dfrac{∆ \theta}{2}\right)