The current voltage relation of diode is given by I = (e 1000 V/T -...

The current voltage relation of diode is given by I = (e¹⁰⁰⁰^V/T - 1) mA, where the applied voltage V is in volts and the temperature T is in degree Kelvin. If a student makes an error measuring

\pm \text{0.01 V}

while measuring the current of 5 mA at 300 K, what will be the error in the value of current in mA ?

Options

A0.2 mA
B0.02 mA
C0.5 mA
D0.05 mA

Correct answer

A. 0.2 mA

Step-by-step solution

\text{I} = \left({\text{e}}^{\text{1000} \text{V} / \text{T}} - 1\right) \text{mA}

\text{When} \text{I} = 5 \text{mA} \text{,} {\text{e}}^{\text{1000} \text{V} / \text{T}} = 6 \text{mA}

Also,

\text{dI} = \left({\text{e}}^{\text{1000} \text{V} / \text{T}}\right) × \dfrac{\text{1000}}{\text{T}} &middot; \text{dV}

= \left(6 \text{mA}\right) × \dfrac{\text{1000}}{\text{300}} × \left(\text{0.01}\right)

= \text{0.2} \text{mA}

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