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A solid steel ball of diameter 3.6 mm acquired terminal velocity 2.45 10⁻² ~m / s while falling under gravity through an oil of density 925 ~kg ~m ⁻³ . Take density of steel as 7825 ~kg ~m ⁻³ and g as 9.8 m / s ^2 . The viscosity of the oil in SI unit is

Options

  1. A2.18
  2. B2.38
  3. C1.68
  4. D1.99

Correct answer

D. 1.99

Step-by-step solution

v _ T 2 9 ( ₀- _ ) r ^2 ~g aligned & = 2 9 ( 7825-925 2.45 10⁻² ) (1.8)^2 10⁻⁶ 9.8 & 1.99 aligned

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