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JEE Main 202528 JanuaryEvening Shift
Exam
JEE Main
Year
2025
Date
28 January
Shift
Evening Shift
Subject
Physics
Chapter
Mechanical Properties of Fluids

JEE Main 2025 · 28 January · Evening Shift · Physics · Mechanical Properties of Fluids

A 400 g solid cube having an edge of length 10 cm floats in water....

A 400 g solid cube having an edge of length 10 cm floats in water. How much volume of the cube is outside the water ? (Given : density of water =1000 kg m−3=1000 \mathrm{~kg} \mathrm{~m}^{-3} )

Options

  1. A1400 cm31400 \mathrm{~cm}^3
  2. B600 cm3600 \mathrm{~cm}^3
  3. C4000 cm34000 \mathrm{~cm}^3
  4. D400 cm3400 \mathrm{~cm}^3

Correct answer

B. 600 cm3600 \mathrm{~cm}^3

Step-by-step solution

Volume of cube inside water =( Denslty of  cube  Denslty of water )× Volume of cube = Mass of cube  Denslty of water =400gm1gm/cm3=400cm3\begin{aligned} & =\left(\frac{\text{ Denslty\text{ of } cube }}{\text{ Denslty of water }}\right) \times \text{ Volume of cube } \\ & =\frac{\text{ Mass of cube }}{\text{ Denslty of water }} \\ & =\frac{400 \mathrm{gm}}{1 \mathrm{gm} / \mathrm{cm}^3} \\ & =400 \mathrm{ cm}^3 \end{aligned} Volume of cube outside water = Volume of  cube − Volume of cube inside water =1000cm3−400cm3=600cm3\begin{aligned} & =\text{ Volume\text{ of } cube }- \text{ Volume of cube inside water } \\ & =1000 \mathrm{ cm}^3-400 \mathrm{ cm}^3 \\ & =600 \mathrm{ cm}^3 \end{aligned}
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