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JEE Main 202522 JanuaryEvening Shift
Exam
JEE Main
Year
2025
Date
22 January
Shift
Evening Shift
Subject
Physics
Chapter
Mechanical Properties of Fluids

JEE Main 2025 · 22 January · Evening Shift · Physics · Mechanical Properties of Fluids

A tube of length L is shown in the figure. The radius of cross...

A tube of length L is shown in the figure. The radius of cross section at the point (1) is 2 cm and at the point (2) is
A tube of length LL is shown in the figure. The radius of cross section at the point (1) is 2 cm and at the point (2) is 1 cm , respectively. If the velocity of water entering at point (1) is 2 m/s2 \mathrm{~m} / \mathrm{s}, then velocity of water leaving the point (2) will be

Options

  1. A4 m/s4 \mathrm{~m} / \mathrm{s}
  2. B2 m/s2 \mathrm{~m} / \mathrm{s}
  3. C6 m/s6 \mathrm{~m} / \mathrm{s}
  4. D8 m/s8 \mathrm{~m} / \mathrm{s}

Correct answer

D. 8 m/s8 \mathrm{~m} / \mathrm{s}

Step-by-step solution

A tube of length L is shown in the figure. The radius of cross section at the point (1) is 2 cm and at the point (2) is
A1 V1=A2 V2⇒2π(2R)2=V2πR2∴ V2=8 m/s\begin{aligned} & \mathrm{A}_1 \mathrm{~V}_1=\mathrm{A}_2 \mathrm{~V}_2 \Rightarrow 2 \pi(2 \mathrm{R})^2=\mathrm{V}_2 \pi \mathrm{R}^2 \\ & \therefore \mathrm{~V}_2=8 \mathrm{~m} / \mathrm{s}\end{aligned}
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