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JEE Main 20244 AprilMorning Shift
Exam
JEE Main
Year
2024
Date
4 April
Shift
Morning Shift
Subject
Physics
Chapter
Mechanical Properties of Fluids

JEE Main 2024 · 4 April · Morning Shift · Physics · Mechanical Properties of Fluids

A soap bubble is blown to a diameter of 7 ~cm .36960 erg of work is...

A soap bubble is blown to a diameter of 7 cm.36960erg7 \mathrm{~cm} .36960 \mathrm{erg} of work is done in blowing it further. If surface tension of soap solution is 40dyne/cm40 \mathrm{dyne} / \mathrm{cm} then the new radius is______ cm\mathrm{cm} Take (π=227)\left(\pi=\frac{22}{7}\right)

Correct answer

0

Step-by-step solution

ω=ΔU=SΔA36960erg=40 dyne cm8π[(r)2−(72)2]cm2r=7cm\begin{aligned} & \omega=\Delta \mathrm{U}=\mathrm{S} \Delta \mathrm{A} \\ & 36960 \mathrm{erg}=\frac{40 \text{ dyne }}{\mathrm{cm}} 8 \pi\left[(\mathrm{r})^2-\left(\frac{7}{2}\right)^2\right] \mathrm{cm}^2 \\ & \mathrm{r}=7 \mathrm{ cm}\end{aligned}
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