There is an air bubble of radius 1 . 0 mm in a liquid of surface tension 0 . 075 N m – 1 and density 1000 kg m – 3 at a depth of 10 cm below the free surface. The amount by which the pressure inside the bubble is greater than the atmospheric pressure is _______ P a g = 10 m s - 2 .

Step-by-step solution

The pressure inside the bubble is given by Δ P = P - P 0 = ρ g h + 2 T r The data given is r = 10 - 3   m T = 0 . 075   N   m - 1 ρ = 1000   kg   m - 3 h = 10   cm Therefore, the pressure in the bubble is Δ P = 1000 × 10 × 10 × 10 - 2 + 2 × 0 . 075 10 - 3 = 1000 + 150 = 1150   P a