Figure below shows a liquid being pushed out of the tube by a piston having area of cross section 2 . 0 cm 2 . The area of cross section at the outlet is 10 mm 2 . If the piston is pushed at a speed of 4 cm s - 1 , the speed of outgoing fluid is _____ cm s - 1

Step-by-step solution

The given data is A 1 = 2 × 10 - 4   m 2 A 2 = 10 × 10 - 6   m 2 v 1 = 4   cm   s - 1 Using equation of continuity which is a conservation of mass principle, A 1 v 1 = A 2 v 2 ⇒ v 2 = A 1 v 1 A 2 = 2 × 10 - 4 × 4 10 × 10 - 6 =   80   cm   s - 1