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JEE Main 202310 AprilEvening Shift
Exam
JEE Main
Year
2023
Date
10 April
Shift
Evening Shift
Subject
Physics
Chapter
Mechanical Properties of Fluids

JEE Main 2023 · 10 April · Evening Shift · Physics · Mechanical Properties of Fluids

Figure below shows a liquid being pushed out of the tube by a...

Figure below shows a liquid being pushed out of the tube by a piston having area of cross section 2.0cm22 . 0{cm}^{2}. The area of cross section at the outlet is 10mm210{mm}^{2}. If the piston is pushed at a speed of 4cms−14cm{s}^{- 1}, the speed of outgoing fluid is _____ cms−1cm{s}^{- 1}

Figure below shows a liquid being pushed out of the tube by a piston having area of cross section 2 . 0 cm ^ 2 . The

Correct answer

0

Step-by-step solution

The given data is

A1=2×10−4m2A2=10×10−6m2v1=4cms−1{A}_{1} = 2 \times {10}^{- 4}{m}^{2}{A}_{2} = 10 \times {10}^{- 6}{m}^{2}{v}_{1} = 4cm{s}^{- 1}

Using equation of continuity which is a conservation of mass principle,

A1v1=A2v2{A}_{1}{v}_{1} = {A}_{2}{v}_{2}

⇒v2=A1v1A2=2×10−4×410×10−6⇒ {v}_{2} = \dfrac{{A}_{1}{v}_{1}}{{A}_{2}} = \dfrac{2 \times {10}^{- 4} \times 4}{10 \times {10}^{- 6}}

=80cms−1= 80cm{s}^{- 1}

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