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JEE Main202329 Jan 2023Morning ShiftPhysicsMechanical Properties of FluidsActual

Surface tension of a soap bubble is 2 . 0 × 10 - 2 N m - 1 . Work done to increase the radius of soap bubble from 3 . 5 cm to 7 cm will be : [Take π = 22 7 ]

Options

  1. A0 . 72 × 10 - 4   J
  2. B5 . 76 × 10 - 4   J
  3. C18 . 48 × 10 - 4   J
  4. D9 . 24 × 10 - 4   J

Correct answer

C. 18 . 48 × 10 - 4   J

Step-by-step solution

As we know, Work done = change in surface energy of soap bubble Therefore, Work done = 2 T 4 π r 2 2 - 4 π r 1 2 = 8 π T r 2 2 - r 1 2 = 8 × 22 7 × 0 . 02 7 2 - 3 . 5 2 × 10 - 4   J = 18 . 48 × 10 - 4 J

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