A water drop of diameter 2cm is broken into 64 equal droplets. The...

By conserving the total volume $\dfrac{4}{3}\pi{R}^{3} = 64 \times \left(\dfrac{4}{3}\pi{r}^{3}\right)$⇒ R = 4r$</p><p>Change in surface energy is</p><p>$\DeltaU = T \times \DeltaA$,$= T\left[64 \times 4\pi{r}^{2} - 4\pi{R}^{2}\right]$</p><p>$= 4\piT{R}^{2}\left[64 \times \dfrac{1}{16} - 1\right] = 12 \times 3 . 14 \times 0 . 075 \times {10}^{- 4}$</p><p>$\approx 2 . 8 \times {10}^{- 4}J