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JEE Main 202117 MarchEvening Shift
Exam
JEE Main
Year
2021
Date
17 March
Shift
Evening Shift
Subject
Physics
Chapter
Mechanical Properties of Fluids

JEE Main 2021 · 17 March · Evening Shift · Physics · Mechanical Properties of Fluids

Suppose you have taken a dilute solution of oleic acid in such a...

Suppose you have taken a dilute solution of oleic acid in such a way that its concentration becomes 0.01cm30 . 01{cm}^{3} of oleic acid per cm3{cm}^{3} of the solution. Then you make a thin film of this solution (monomolecular thickness) of area 4cm24{cm}^{2} by considering 100100 spherical drops of radius \left(\dfrac{3}{40\pi}\right)\dfrac{1}{3} \times {10}^{- 3}cm .ThenthethicknessofoleicacidlayerwillbeThen the thickness of oleic acid layer will bex \times {10}^{- 14}m.Where. Wherex is ________ .

Correct answer

0

Step-by-step solution

4tT=100×43\pir34{t}_{T} = 100 \times \dfrac{4}{3}\pir^{3}

=100×4π3×340π×10−9=10−8cm3= 100 \times \dfrac{4\pi}{3} \times \dfrac{3}{40\pi} \times {10}^{- 9} = {10}^{- 8}{cm}^{3}

tT=25×10−10cm=25×10−12m{t}_{T} = 25 \times {10}^{- 10}cm= 25 \times {10}^{- 12}m

t0=0.01tT=25×10−14m⇒x=25{t}_{0} = 0 . 01{t}_{T} = 25 \times {10}^{- 14}m⇒ x = 25.

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