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JEE Main 202116 MarchEvening Shift
Exam
JEE Main
Year
2021
Date
16 March
Shift
Evening Shift
Subject
Physics
Chapter
Mechanical Properties of Fluids

JEE Main 2021 · 16 March · Evening Shift · Physics · Mechanical Properties of Fluids

What will be the nature of flow of water from a circular tap, when...

What will be the nature of flow of water from a circular tap, when its flow rate increased from 0.18L(min)−10 . 18L{\left(min\right)}^{- 1} to 0.48L(min)−1?0 . 48L{\left(min\right)}^{- 1} ? The radius of the tap and viscosity of water are 0.5cm0 . 5cm and 10−3Pas{10}^{- 3}Pas, respectively. (Density of water : 103kgm−3{10}^{3}kg{m}^{- 3})

Options

  1. AUnsteady to steady flow
  2. BRemains steady flow
  3. CRemains turbulent flow
  4. DSteady flow to unsteady flow

Correct answer

D. Steady flow to unsteady flow

Step-by-step solution

The nature of flow is determined by Reynolds
Number.

Re=ρvDη{R}_{e} = \dfrac{ρvD}{η}

\left[ρ→densityoffluid;η→coefficientofvelocityv→velocityofflowD→Diameterofpipe\begin{array}{ll}ρ \to densityoffluid; η \to coefficientofvelocity \\ v \to velocityofflow \\ D \to Diameterofpipe\end{array}\right]</p><p>FromNCERT</p><p>If</p><p>From NCERT </p><p>If{R}_{e} < 1000 \toflowissteady</p><p>flow is steady</p><p>1000 < {R}_{p} < 2000 \toflowbecomesunsteady</p><p>flow becomes unsteady</p><p>{R}_{e} > 2000 \toflowisturbulent</p><p>flow is turbulent </p><p>{R}_{einitial} = {10}^{3} \times \dfrac{0 . 18 \times {10}^{- 3}}{\pi \times {\left(0 . 5 \times {10}^{- 2}\right)}^{2} \times 60} \times \dfrac{1 \times {10}^{- 2}}{{10}^{- 3}}</p><p></p><p>= 382 . 16</p><p></p><p>{R}_{efinal} = {10}^{3} \times \dfrac{0 . 48 \times {10}^{- 3}}{\pi \times {\left(0 . 5 \times {10}^{- 2}\right)}^{2} \times 60} \times \dfrac{1 \times {10}^{- 2}}{{10}^{- 3}}</p><p></p><p>= 1019 . 09$

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