A liquid of density is coming out of a hose pipe of radius a with horizontal speed v and hits a mesh. 50 % of the liquid passes through the mesh unaffected. 25 % looses all of its momentum and 25 % comes back with the same speed. The resultant pressure on the mesh will be:

Step-by-step solution

Mass per unit time of the liquid = Momentum per second carried by liquid = a v v Net force due to bounced back liquid, F ₁=2 [ 1 4 av ² ] Net force due to stopped liquid, F ₂= 1 4 pav ² Total force, F = F ₁+ F ₂= 1 2 av ²+ 1 4 pav ²= 3 4 pav ² Net pressure = 3 4 v²