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JEE Main20199 Jan 2019Evening ShiftPhysicsMechanical Properties of FluidsActual

The top of a water tank is open to air and its water level is maintained. It is giving out 0.74 m 3 water per minute through a circular opening of 2 cm radius in its wall. The depth of the centre of the opening from the level of water in the tank is close to:

Options

  1. A2.9   m
  2. B4.8   m
  3. C6.0   m
  4. D9.6   m

Correct answer

B. 4.8   m

Step-by-step solution

Volume of water flowing out = A v , where A is area of opening and v is speed of water from the opening. Volume = π r 2 v 0 . 74     m 3 min = 3.14 × 2 × 10 - 2 2 × 2 × 10 × H   m 3 s × 60   s min ⇒ H = 0.74 60 × 3.14 × 4 × 10 - 4 2 × 1 20 ⇒ H = 4.8   m Hence, the height of water in the tank was 4 . 8   m from the bottom of the tank.

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