In the diagram shown, the difference in the two tubes of the manometer is 5 cm , the cross-section of the tube at A and B is 6 mm 2 and 10 mm 2 respectively. The rate at which water flows through the tube is g = 10 m s - 2

Step-by-step solution

6 v A = 10 v B     . . . . . . 1 1 2 ρ v A 2 - ρ g h = 1 2 ρ v B 2 .........(2) ⇒ v A = 1 0 .8   m   s - 1 d V d t = A v A = 6 × 10 - 2   cm 2 × 100 0 .8   cm   s - 1 = 7 . 5   cc   s - 1 OR By the concept of the venturi meter tube rate of flow = Q = A 1 A 2 2 g ( h 1 − h 2 ) ( A 2 2 − A 1 2 ) = 6 × 10 × 10 − 4 2 × 100 × 5 ( − 36 + 100 ) × 10 − 2 = 7 .5   cc   s - 1