A capillary tube is immersed vertically in water and the height of the water column is x ⁡ . When this arrangement is taken into a mine of depth d, the height of the water column is y ⁡ . If R is the radius of earth, the ratio x ⁡ y ⁡ is :

Step-by-step solution

We know that h = 2 T cos θ ρ gr ∴    x = 2 T cos θ ρ gr Now, value of g eff at depth 'd' is g eff = g 1 - d R ∴    y = 2 T cos θ ρ g eff · r ∴    x y = g eff g = 1 - d R