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An open glass tube is immersed in mercury in such a way that a length of 8 cm extends above the mercury level. The open end of the tube is then closed and sealed and the tube is raised vertically up by additional 46 cm . What will be length of the air column above mercury in the tube now ? (Atmospheric pressure = 76 cm of Hg)

Options

  1. A16   cm
  2. B22   cm
  3. C38   cm
  4. D6   cm

Correct answer

A. 16   cm

Step-by-step solution

Using isothermal process conditions ⇒ P 1 V 1 = P 2 V 2 ⇒ P 1 A ℓ 1 = P 2 A ℓ 2 8 p 0 = xp ⇒ p = 8 p 0 x (here p 0 = 76 cm of Hg) 8 p 0 x + ρ m g 54 - x = ρ m g (76) 8 x + 54 - x 76 = 1 x = 16 cm

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