An open glass tube is immersed in mercury in such a way that a...

Using isothermal process conditions



$⇒ {P}_{1} {V}_{1} = {P}_{2} {V}_{2} ⇒ {P}_{1} A{ℓ}_{1} = {P}_{2} A{ℓ}_{2}$

${8 \text{p}}_{{}_{0}} = \text{xp} ⇒ \text{p} = \dfrac{8 {\text{p}}_{0}}{\text{x}}$ (here p₀ = 76 cm of Hg)

$\dfrac{8 {\text{p}}_{0}}{\text{x}} + {\text{ρ}}_{\text{m}} \text{g} \left(\text{54} - \text{x}\right) = {\text{ρ}}_{\text{m}} \text{g} \text{(76)}$

$\dfrac{8}{\text{x}} + \dfrac{\text{54} - \text{x}}{\text{76}} = 1$

x = 16 cm