In an experiment, a small steel ball falls through a liquid at a...

Weight of the body $\mathrm{W}=\mathrm{mg}=\frac{4}{3} \pi \mathrm{r}^3 \rho \mathrm{g}$ $\mathrm{T}=\frac{4}{3} \pi \mathrm{r}^3 \sigma \mathrm{g}$ and $\mathrm{F}=6 \pi \eta \mathrm{vr}$ When the body attains terminal velocity net force acting on the body is zero. i.e., $\mathrm{W}-\mathrm{T}-\mathrm{F}=0$ And terminal velocity $\mathrm{v}=\frac{2}{9} \frac{\mathrm{r}^2(\rho-\sigma) \mathrm{g}}{\eta}$ As in case of upward motion upward force is twice its effective weight, therefore, it will move with same speed $10 \mathrm{~cm} / \mathrm{s}$