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Air of density 1.2 ~kg ~m ⁻³ is blowing across the horizontal wings of an aeroplane in such a way that its speeds above and below the wings are 150 ~ms ⁻¹ and 100 ~ms ⁻¹ , respectively. The pressure difference between the upper and lower sides of the wings, is :

Options

  1. A60 Nm ⁻²
  2. B180 Nm ⁻²
  3. C7500 Nm ⁻²
  4. D12500 Nm ⁻²

Correct answer

C. 7500 Nm ⁻²

Step-by-step solution

Pressure difference aligned & P ₂- P ₁= 1 2 ( v ₂^2- v ₁^2 ) & = 1 2 1.2 ((150)^2-(100)^2 ) & = 1 2 1.2(22500-10000) & =7500 Nm ⁻² aligned

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