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JEE Main 201226 MayOnline
Exam
JEE Main
Year
2012
Date
26 May
Mode
Online
Subject
Physics
Chapter
Mechanical Properties of Fluids

JEE Main 2012 · 26 May · Online · Physics · Mechanical Properties of Fluids

In a cylindrical water tank, there are two small holes A and B on...

In a cylindrical water tank, there are two small holes AA and BB on the wall at a depth of h1h_1, from the surface of water and at a height of h2h_2 from the bottom of water tank. Surface of water is at height of h2h_2 from the bottom of water tank. Surface of water is at heigh HH from the bottom of water tank. Water coming out from both holes strikes the ground at the same point SS. Find the ratio of h1h_1 and h2h_2 In a cylindrical water tank, there are two small holes A and B on the wall at a depth of h_1 , from the surface of

Options

  1. ADepends on HH
  2. B1:11: 1
  3. C2:22: 2
  4. D1:21: 2

Correct answer

A. Depends on HH

Step-by-step solution

Range is same for both holes \therefore 2 (H−h1)h1=2(H−h2)h2\sqrt{\left(\mathrm{H}-h_1\right) h_1}=2 \sqrt{\left(\mathrm{H}-h_2\right) h_2} Squaring both sides, 4(H−h1)h1=4(H−h2)h2Hh1−h12=Hh2−h22\begin{aligned}& 4 \left(H-h_1\right)\mathrm{h}_{1}=4\left(H-h_2\right) h_2 \\ & H h_1-h_1^2=H h_2-h_2^2 \end{aligned}On solving we get, H=h_1+h_2 Hence,thetheratio of \frac{h_1}{h_2} depends on$ H.
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