The increase in the pressure required to decrease the volume (Δ V) of water is 6.3 × 10^7 N/m ^2 . The percentage decrease in the volume is _____. (Bulk modulus of water = 2.1 × 10^9 N/m ^2 .)

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Correct answer: B. 3\%

Bulk modulus is given by B = (Δ P)/(-(Δ V)/(V)) The fractional decrease in volume is -(Δ V)/(V) = (Δ P)/(B) Substituting the given values: -(Δ V)/(V) = (6.3 × 10^7)/(2.1 × 10^9) = 3 × 10^ -2 The percentage decrease in volume is (-(Δ V)/(V)) × 100 Percentage decrease = 3 × 10^ -2 × 100 = 3\% Answer: 3\%

The increase in the pressure required to decrease the volume (Δ V)...

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