A sample of a liquid is kept at 1 atm. It is compressed to 5 atm...

Given, Initial pressure of liquid $\left(P_i\right)=1 \mathrm{~atm}$
Final pressure of liquid \left(\mathrm{P}_{\mathrm{f}}\right)=5 \mathrm{~atm}$<br/>Change in pressure$(\mathrm{dP})=\mathrm{P}_{\mathrm{f}}-\mathrm{P}_{\mathrm{i}}=4 \mathrm{~atm}$<br/>$=4 \times 10^5 \mathrm{~Pa}$<br/>Change in volume$(\mathrm{dV})=-0.8 \mathrm{~cm}^3$<br/>Bulk modulus$(B)=2 \times 10^9 \mathrm{~Pa}$<br/>Now,$B=\frac{-d P}{(d V / V)} \Rightarrow V=-B\left(\frac{d V}{d P}\right)$<br/>$$\begin{aligned}<br/>\Rightarrow & V=-2 \times 10^9 \times \frac{\left(-0.8 \times 10^{-6}\right)}{4 \times 10^5} \\ & =4 \times 10^{-3} \mathrm{~m}^3=4 \text{ litre }<br/>\end{aligned}$$