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JEE Main20254 Apr 2025Morning ShiftPhysicsMechanical Properties of SolidsActual

Two slabs with square cross section of different materials (1,2) with equal sides (l) and thickness d ₁ and d ₂ such that d ₂=2 ~d ₁ and l d ₂ . Considering lower edges of these slabs are fixed to the floor, we apply equal shearing force on the narrow faces. The angle of deformation is ₂=2 ₁ . If the shear moduli of material 1 is 4 10^9 ~N / m ^2 , then shear moduli of material 2 is x 10^9 ~N / m ^2 , where value of

Correct answer

0

Step-by-step solution

Deformation angle aligned & 2 ₁= ₂ & 2 ₁ ₁ = ₂ ₂ aligned aligned & 2 ( ~F ~d ₁ ₁ )= F d ₂ ₂ & ₂= ₁ 4 =1 10^9 x=1 aligned

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