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One end of a metal wire is fixed to a ceiling and a load of 2 kg hangs from the other end. A similar wire is attached to the bottom of the load and another load of 1 kg hangs from this lower wire. Then the ratio of longitudinal strain of upper wire to that of the lower wire will be [Area of cross section of wire = 0 . 005 cm 2 , Y = 2 × 10 11 N m - 2 and g = 10 m s - 2 ]

Correct answer

3

Step-by-step solution

As we know, change in length is given by Δ L = F L A Y Therefore, strain required Δ L L = F A Y Now the ratio will be, Δ L 1 L 1 Δ L 2 L 2 = F 1 F 2 = T 1 T 2 = 30 10 = 3

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