A certain pressure ' P ' is applied to 1 litre of water and 2 litre...

Bulk modulus is given by $B = \dfrac{- \DeltaP}{\left(\dfrac{\DeltaV}{V}\right)}$

Now, in case of water, ${B}_{water} = \dfrac{- \DeltaP}{\left(\dfrac{\DeltaV}{V}\right)} = \dfrac{- \DeltaP}{\dfrac{0 . 01}{100}}$

In case of liquid, ${B}_{liquid} = \dfrac{- \DeltaP}{\dfrac{0 . 03}{100}}$

Thus, the ratio $\dfrac{{B}_{water}}{{B}_{liquid}} = \dfrac{\dfrac{- \DeltaP}{0 . 0001}}{\dfrac{- \DeltaP}{0 . 0003}} = 3$

Hence, the value of $x = 1$.