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JEE Main 202224 JuneMorning Shift
Exam
JEE Main
Year
2022
Date
24 June
Shift
Morning Shift
Subject
Physics
Chapter
Mechanical Properties of Solids

JEE Main 2022 · 24 June · Morning Shift · Physics · Mechanical Properties of Solids

The bulk modulus of a liquid is 3 × 10 ^ 10 Nm ^ - 2 . The pressure...

The bulk modulus of a liquid is 3×1010Nm−23 \times {10}^{10}{Nm}^{- 2}. The pressure required to reduce the volume of liquid by 22 % is :

Options

  1. A3×108Nm−23 \times {10}^{8}N{m}^{- 2}
  2. B6×108Nm−26 \times {10}^{8}N{m}^{- 2}
  3. C9×108Nm−29 \times {10}^{8}N{m}^{- 2}
  4. D12×108Nm−212 \times {10}^{8}N{m}^{- 2}

Correct answer

B. 6×108Nm−26 \times {10}^{8}N{m}^{- 2}

Step-by-step solution

Bulk modulus B=VolumetricstressVolumetricstrain=−∆P∆VVB = \dfrac{Volumetricstress}{Volumetricstrain} = \dfrac{- ∆ P}{\dfrac{∆ V}{V}}

Then, ∆P=B×(−∆VV)=3×1010×2100=6×108Nm−2∆ P = B \times \left(- \dfrac{∆ V}{V}\right) = 3 \times {10}^{10} \times \dfrac{2}{100} = 6 \times {10}^{8}N{m}^{- 2}

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