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JEE Main 202126 AugustEvening Shift
Exam
JEE Main
Year
2021
Date
26 August
Shift
Evening Shift
Subject
Physics
Chapter
Mechanical Properties of Solids

JEE Main 2021 · 26 August · Evening Shift · Physics · Mechanical Properties of Solids

Two blocks of masses 3kg and 5kg are connected by a metal wire...

Two blocks of masses 3kgand5kg3kg and 5kg are connected by a metal wire going over a smooth pulley. The breaking stress of the metal is 24π×102Nm−2\dfrac{24}{\pi} \times {10}^{2}N{m}^{- 2}. What is the minimum radius of the wire ?
( take \leftg = 10{ms}^{- 2})

Two blocks of masses 3kg and 5kg are connected by a metal wire going over a smooth pulley. The breaking stress of the

Options

  1. A1250cm1250cm
  2. B1.25cm1 . 25cm
  3. C125cm125cm
  4. D12.5cm12 . 5cm

Correct answer

D. 12.5cm12 . 5cm

Step-by-step solution

Tension in the string =2m1m2(m1+m2)g= \dfrac{2{m}_{1}{m}_{2}}{\left({m}_{1} + {m}_{2}\right)}g

=2×3×5×108=752= \dfrac{2 \times 3 \times 5 \times 10}{8} = \dfrac{75}{2}

Stress =TA= \dfrac{T}{A}

24π×102=752(πr2)\dfrac{24}{\pi} \times {10}^{2} = \dfrac{75}{2\left(\pi{r}^{2}\right)}

r2=7548×10−2{r}^{2} = \dfrac{75}{48} \times {10}^{- 2}

r2=0.015625{r}^{2} = 0 . 015625

r=0.125m=12.5cmr = 0 . 125m = 12 . 5cm

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