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JEE Main 2003
Exam
JEE Main
Year
2003
Subject
Physics
Chapter
Mechanical Properties of Solids

JEE Main 2003 · Physics · Mechanical Properties of Solids

A wire suspended vertically from one of its ends is stretched by...

A wire suspended vertically from one of its ends is stretched by attaching a weight of 200 N200 \mathrm{~N} to the lower end. The weight stretches the wire by 1 mm1 \mathrm{~mm}. Then the elastic energy stored in the wire is

Options

  1. A0.2 J0.2 \mathrm{~J}
  2. B10 J10 \mathrm{~J}
  3. C20 J20 \mathrm{~J}
  4. D0.1 J0.1 \mathrm{~J}

Correct answer

D. 0.1 J0.1 \mathrm{~J}

Step-by-step solution

Elastic energy =12×F×xF==\frac{1}{2} \times \mathrm{F} \times \mathrm{x}\mathrm{F}=200  N,x=\mathrm{~N}, \mathrm{x}=1  mm=\mathrm{~mm}=10^{-3}  m∴E=12×\mathrm{~m} \quad \therefore \mathrm{E}=\frac{1}{2} \times200 ×\times1 ×\times10^{-3}=0.1  J\mathrm{~J}
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