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JEE Main 20257 AprilEvening Shift
Exam
JEE Main
Year
2025
Date
7 April
Shift
Evening Shift
Subject
Physics
Chapter
Motion in One Dimension

JEE Main 2025 · 7 April · Evening Shift · Physics · Motion in One Dimension

A helicopter flying horizontally with a speed of 360 ~km / h at an...

A helicopter flying horizontally with a speed of 360 km/h360 \mathrm{~km} / \mathrm{h} at an altitude of 2 km , drops an object at an instant. The object hits the ground at a point O , 20 s after it is dropped. Displacement of ' O ' from the position of helicopter where the object was released is :
(use acceleration due to gravity g=10 m/s2\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2 and neglect air resistance)A helicopter flying horizontally with a speed of 360 ~km / h at an altitude of 2 km , drops an object at an instant.

Options

  1. A25 km2 \sqrt{5} \mathrm{~km}
  2. B4 km
  3. C7.2 km
  4. D22 km2 \sqrt{2} \mathrm{~km}

Correct answer

D. 22 km2 \sqrt{2} \mathrm{~km}

Step-by-step solution

A helicopter flying horizontally with a speed of 360 ~km / h at an altitude of 2 km , drops an object at an instant.
u=360×518=100 m/sx=u×t=2×103 mt=2Hg⇒H=t2 g2H=400×102H=2000 mD=x2+H2D=22 km\begin{aligned} & \mathrm{u}=360 \times \frac{5}{18}=100 \mathrm{~m} / \mathrm{s} \\ & \mathrm{x}=\mathrm{u} \times \mathrm{t}=2 \times 10^3 \mathrm{~m} \\ & \mathrm{t}=\sqrt{\frac{2 \mathrm{H}}{\mathrm{g}}} \Rightarrow \mathrm{H}=\frac{\mathrm{t}^2 \mathrm{~g}}{2} \\ & \mathrm{H}=\frac{400 \times 10}{2} \\ & \mathrm{H}=2000 \mathrm{~m} \\ & \mathrm{D}=\sqrt{\mathrm{x}^2+\mathrm{H}^2} \\ & \mathrm{D}=2 \sqrt{2} \mathrm{~km}\end{aligned}
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