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JEE Main 202528 JanuaryEvening Shift

Exam: JEE Main
Year: 2025
Date: 28 January
Shift: Evening Shift
Subject: Physics
Chapter: Motion in One Dimension

JEE Main 2025 · 28 January · Evening Shift · Physics · Motion in One Dimension

The velocity-time graph of an object moving along a straight line...

The velocity-time graph of an object moving along a straight line is shown in figure. What is the distance covered by the object between

t=0

to

t=4 \mathrm{~s}

?

The velocity-time graph of an object moving along a straight line is shown in figure. What is the distance covered by

Options

A $30\mathrm{~m}$
B $11\mathrm{~m}$
C $10\mathrm{~m}$
D $13\mathrm{~m}$

Correct answer

A. $30\mathrm{~m}$

Step-by-step solution

Distance travelled = displacement when direction of velocity remains constant

\begin{aligned} \Rightarrow \text{ Distance } & =\text{ Area } \\ & =\frac{1}{2}(2 \mathrm{ s}+4 \mathrm{ s})(10 \mathrm{ m} / \mathrm{s}) \\ & =30 \mathrm{ m}\end{aligned}

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