JEE Main20241 Feb 2024Evening ShiftPhysicsMotion in One DimensionActual
A particle initially at rest starts moving from reference point x = 0 along x -axis, with velocity v that varies as v = 4 x m s - 1 . The acceleration of the particle is _____ m s - 2 .
Correct answer
0
Step-by-step solution
Given: v = 4 x Instantaneous acceleration of the particle can be written as, a = v d v d x = 4 x × 4 × 1 2 x - 1 / 2 = 8 m s - 2