The displacement and the increase in the velocity of a moving particle in the time interval of t to ( t + 1 ) s are 125 m and 50 m s - 1 , respectively. The distance travelled by the particle in ( t + 2 ) th s is ___________ m .

Step-by-step solution

Considering acceleration is constant, we can write v = u + a t As increase in velocity in 1 s is given as 50 m s - 1 , therefore ⇒ a = 50 m s - 2 Now, displacement covered between given time interval is, 125 = u t + 1 2 a t 2 ⇒ 125 = u + a 2 ⇒ u = 100 m s - 1 Velocity after 1 s will be, v = 100 + 50 = 150 m s - 1 Therefore, displacement covered in t + 1 s to t + 2 s will ∴ S n t h = v t ' + 1 2 a t ' 2 , where t ' = 1 s = 175 m