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JEE Main 202427 JanuaryMorning Shift
Exam
JEE Main
Year
2024
Date
27 January
Shift
Morning Shift
Subject
Physics
Chapter
Motion in One Dimension

JEE Main 2024 · 27 January · Morning Shift · Physics · Motion in One Dimension

Position of an ant ( S in metres) moving in Y - Z plane is given by...

Position of an ant ( SS in metres) moving in Y−ZY - Z plane is given by S = 2{t}^{2}\overset{^}{j} + 5\overset{^}{k} (where tt is in second). The magnitude and direction of velocity of the ant at t=1st = 1s will be :

Options

  1. A16ms−116m{s}^{- 1} in y-direction
  2. B4ms−14m{s}^{- 1} in xx-direction
  3. C9ms−19m{s}^{- 1} in z-direction
  4. D4ms−14m{s}^{- 1} in yy-direction

Correct answer

D. 4ms−14m{s}^{- 1} in yy-direction

Step-by-step solution

The velocity of the ant can be found as follows:

\begin{cases}\overset{\to}{v} & = & \dfrac{d\overset{\to}{S}}{dt} \\ & = & \dfrac{d}{dt}\left(2{t}^{2}\overset{^}{j} + 5\overset{^}{k}\right) \\ & = & 4t\overset{^}{j} . . . \left(1\right)\end{cases}

At t=1st = 1s, from equation (1), it follows that

\overset{\to}{v} = 4\overset{^}{j}

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