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JEE Main 202330 JanuaryMorning Shift
Exam
JEE Main
Year
2023
Date
30 January
Shift
Morning Shift
Subject
Physics
Chapter
Motion in One Dimension

JEE Main 2023 · 30 January · Morning Shift · Physics · Motion in One Dimension

Match Column-I with Column-II : Column-I (x-t graphs) Column-II...

Match Column-I with Column-II :

Column-I (x-t graphs) Column-II (v-t graphs)
A Match Column-I with Column-II : Column-I (x-t graphs) Column-II (v-t graphs) A I B II C III D IV Choose the correct I Match Column-I with Column-II : Column-I (x-t graphs) Column-II (v-t graphs) A I B II C III D IV Choose the correct
B Match Column-I with Column-II : Column-I (x-t graphs) Column-II (v-t graphs) A I B II C III D IV Choose the correct II Match Column-I with Column-II : Column-I (x-t graphs) Column-II (v-t graphs) A I B II C III D IV Choose the correct
C Match Column-I with Column-II : Column-I (x-t graphs) Column-II (v-t graphs) A I B II C III D IV Choose the correct III Match Column-I with Column-II : Column-I (x-t graphs) Column-II (v-t graphs) A I B II C III D IV Choose the correct
D Match Column-I with Column-II : Column-I (x-t graphs) Column-II (v-t graphs) A I B II C III D IV Choose the correct IV Match Column-I with Column-II : Column-I (x-t graphs) Column-II (v-t graphs) A I B II C III D IV Choose the correct

Choose the correct answer from the options given below:

Options

  1. AA- II B-IV, C-III, D-I
  2. BA- I. B-II, C-III, D-IV
  3. CA- II B-III, C-IV, D-I
  4. DA- I, B-III. C-IV, D-II

Correct answer

A. A- II B-IV, C-III, D-I

Step-by-step solution

(A) Here, the slope dxdt≥0\dfrac{dx}{dt} \ge 0 is always increasing, and we know that the derivative graph of the parabola is straight line, so the graph of velocity-time is straight line with increasing slope.

(A−II)( A - II )

(B) Here, the slope dxdt<0andatt→∞,dxdt→0\dfrac{dx}{dt} < 0andatt \to \infty , \dfrac{dx}{dt} \to 0. As the slope is decreasing with time, so the graph of velocity-time will have negative velocity and positive slope.

(B−IV)( B - IV )

(C) Here, the slope dxdt>0forfirsthalfanddxdt<0forsecondhalf\dfrac{dx}{dt} > 0forfirsthalfand\dfrac{dx}{dt} < 0forsecondhalf.

As the slope of displacement-time is positive constant in first half and negative constant in second half, so the velocity will be uniform positive and uniform negative value.

(C−III)( C - III )

(D) Here, the slope dxdt=constant\dfrac{dx}{dt} = constant.

As the slope of displacement-time is positive constant, so the velocity will be uniform positive value.

(D−I)( D - I )

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