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JEE Main 202325 JanuaryEvening Shift
Exam
JEE Main
Year
2023
Date
25 January
Shift
Evening Shift
Subject
Physics
Chapter
Motion in One Dimension

JEE Main 2023 · 25 January · Evening Shift · Physics · Motion in One Dimension

The distance travelled by a particle is related to time t as x = 4...

The distance travelled by a particle is related to time tt as x=4t2x = 4{t}^{2}. The velocity of the particle at t=5st = 5s is

Options

  1. A40ms–140m{s}^{– 1}
  2. B25ms–125m{s}^{– 1}
  3. C20ms–120m{s}^{– 1}
  4. D8ms–18m{s}^{– 1}

Correct answer

A. 40ms–140m{s}^{– 1}

Step-by-step solution

Given here, x=4t2x = 4{t}^{2}

We know that velocity is the rate at which displacement changes with time. So, v=dxdt=d(4t2)dt=8tv = \dfrac{dx}{dt} = \dfrac{d \left(4{t}^{2}\right)}{d t} = 8t

Now, at t=5st = 5s

Velocity of particle is v=8×5=40ms−1v = 8 \times 5 = 40m{s}^{- 1}.

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