A NCC parade is going at a uniform speed of 9 km h - 1 under a mango tree on which a monkey is sitting at a height of 19 . 6 m . At any particular instant, the monkey drops a mango. A cadet will receive the mango whose distance from the tree at time of drop is : (Given g = 9 . 8 m s - 2 )

Step-by-step solution

If a cadet receives the mango, then the time taken by the mango to fall and the cadet to reach there should be equal. Time taken by mango to fall t = 2 h g . ⇒ t = 2 × 19 . 6 9 . 8 = 2   s Therefore, the distance of the cadet from the tree will be, d = v t . ⇒ d = 9 × 5 18 × 2 = 5   m