A NCC parade is going at a uniform speed of $9km{h}^{- 1}$ under a mango tree on which a monkey is sitting at a height of $19 . 6m$ . At any particular instant, the monkey drops a mango. A cadet will receive the mango whose distance from the tree at time of drop is :
(Given $g = 9 . 8m{s}^{- 2}$ )

Question

A NCC parade is going at a uniform speed of

9km{h}^{- 1}

under a mango tree on which a monkey is sitting at a height of

19 . 6m

. At any particular instant, the monkey drops a mango. A cadet will receive the mango whose distance from the tree at time of drop is :
(Given

g = 9 . 8m{s}^{- 2}

)

Quantrex Academy · Accepted Answer

Correct answer: A. 5m

If a cadet receives the mango, then the time taken by the mango to fall and the cadet to reach there should be equal.
Time taken by mango to fall $t = \sqrt{\dfrac{2h}{g}}$ .
$⇒ t = \sqrt{\dfrac{2 \times 19 . 6}{9 . 8}} = 2s$
Therefore, the distance of the cadet from the tree will be, $d = vt$ .
$⇒ d = 9 \times \dfrac{5}{18} \times 2 = 5m$

A NCC parade is going at a uniform speed of 9km h ^ - 1 under a...

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