A particle is moving in a straight line such that its velocity is increasing at 5 m s - 1 per meter. The acceleration of the particle is _____ m s - 2 at a point where its velocity is 20 m s - 1 .

Step-by-step solution

According to the question, velocity is increasing at 5   m   s - 1 . Therefore, d v d s = 5   s - 1 . Now acceleration a = d v d t = v d v d s ⇒ a = v d v d s = 20 × 5 = 100   m   s - 2