Velocity (v) and acceleration (a) in two systems of units 1 and 2...

Distance is stated as $[ L ] = \dfrac{\left[{v}^{2}\right]}{[ a ]}$

⇒ \dfrac{{\left[{v}_{2}\right]}^{2}}{\left[{a}_{2}\right]} = \dfrac{\left[{\left\dfrac{n}{{m}^{2}}{v}_{1}\right|}^{2}\right\}{{\left[\dfrac{{a}_{1}}{mn}\right]}^{2}}= \dfrac{{n}^{3}}{{m}^{3}}\dfrac{{\left[{v}_{1}\right]}^{2}}{\left[{a}_{1}\right]}

Or, we have \left[{L}_{2}\right] = \dfrac{{n}^{3}}{{m}^{3}}\left[{L}_{1}\right]$</p><p>Similarly, time \left[T\right] = \dfrac{\left[v\right]}{\left[a\right]}$

$⇒ \dfrac{\left[{v}_{2}\right]}{\left[{a}_{2}\right]} = \dfrac{\left[\dfrac{n}{{m}^{2}}{v}_{1}\right]}{\left[\dfrac{{a}_{1}}{mn}\right]} = \dfrac{{n}^{2}}{m}\dfrac{\left[{v}_{1}\right]}{\left[{a}_{1}\right]}$

So, ${T}_{2} = \dfrac{{n}^{2}}{m}{T}_{1}$