JEE Main202228 Jun 2022Morning ShiftPhysicsMotion in One DimensionActual
Motion of a particle in x - y plane is described by a set of following equations x = 4 sin π 2 - ω t m and y = 4 sin ω t m . The path of the particle will be
Options
- Acircular
- Bhelical
- Cparabolic
- Deliptical
Correct answer
A. circular
Step-by-step solution
x = 4 sin π 2 - ω t = 4 cos ω t , y = 4 sin ω t Clearly, x 2 + y 2 = 4 cos ω t 2 + 4 sin ω t 2 ⇒ x 2 + y 2 = 16 Hence, the path covered by particle is a circle.