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JEE Main202126 Feb 2021Evening ShiftPhysicsMotion in One DimensionActual

A scooter accelerates from rest for time t 1 at constant rate a 1 and then retards at constant rate a 2 for time t 2 and comes to rest. The correct value of t 1 t 2 will be :

Options

  1. Aa 2 a 1
  2. Ba 1 a 2
  3. Ca 1 + a 2 a 1
  4. Da 1 + a 2 a 2

Correct answer

A. a 2 a 1

Step-by-step solution

Draw v t curve tan θ 1 = a 1 = v max t 1 &   tan θ 2 = a 2 = v max t 2 ÷ above t 1 t 2 = a 2 a 1

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