JEE Main 202126 FebruaryEvening Shift
- Exam
- JEE Main
- Year
- 2021
- Date
- 26 February
- Shift
- Evening Shift
- Subject
- Physics
- Chapter
- Motion in One Dimension
JEE Main 2021 · 26 February · Evening Shift · Physics · Motion in One Dimension
A scooter accelerates from rest for time t _ 1 at constant rate a _...
A scooter accelerates from rest for time at constant rate and then retards at constant rate for time and comes to rest. The correct value of will be :
Options
- A
- B
- C
- D
Correct answer
A.
Step-by-step solution
Draw curve
tan{\theta}_{1} = {a}_{1} = \dfrac{{v}_\max}{{t}_{1}}
\text{ and } tan{\theta}_{2} = {a}_{2} = \dfrac{{v}_\max}{{t}_{2}}
above