JEE Main202126 Feb 2021Morning ShiftPhysicsMotion in One DimensionActual
A person standing on a spring balance inside a stationary lift measures 60   kg . The weight of that person if the lift descends with uniform downward acceleration of 1 . 8   m   s - 2 will be N . g = 10   m   s - 2
Correct answer
492
Step-by-step solution
When lift is at rest N = m g ⇒ 60 × 10 = 600   N When lift moves with downward acceleration. In frame of lift pseudo force will be in upward direction. N ' = M g - a ⇒ 60 10 - 1 . 8 N ' ⇒ 492   N