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JEE Main 20209 JanuaryMorning Shift
Exam
JEE Main
Year
2020
Date
9 January
Shift
Morning Shift
Subject
Physics
Chapter
Motion in One Dimension

JEE Main 2020 · 9 January · Morning Shift · Physics · Motion in One Dimension

The distance x covered by a paritcle in one dimensional motion...

The distance xx covered by a paritcle in one dimensional motion varies with time tt as x2=at2+2bt+c{x}^{2} = a{t}^{2} + 2bt + c . If the acceleration of the particle depends on xx as x−n{x}^{- n} , where nn is an integer, the value of nn is _________

Correct answer

0

Step-by-step solution

x2=at2+2bt+c{x}^{2} = a{t}^{2} + 2bt + c
2xv=2at+2b2xv = 2at + 2b
xv=at+bxv = at + b
v2+ax=a{v}^{2} + ax = a
ax=a−(at+bx)2ax = a - {\left(\dfrac{at + b}{x}\right)}^{2}
a=a(at2+2bt+c)−(at+b)2x3a = \dfrac{a\left(a{t}^{2} + 2bt + c\right) - {\left(at + b\right)}^{2}}{{x}^{3}}
a=ac−2x3a = \dfrac{a{c}^{- 2}}{{x}^{3}}
aαx−3a\alpha{x}^{- 3}
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