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JEE Main 20198 AprilEvening Shift
Exam
JEE Main
Year
2019
Date
8 April
Shift
Evening Shift
Subject
Physics
Chapter
Motion in One Dimension

JEE Main 2019 · 8 April · Evening Shift · Physics · Motion in One Dimension

A particle starts from origin O from rest and moves with a uniform...

A particle starts from origin OO from rest and moves with a uniform acceleration along the positive x−axisx - axis . Identify all figures that correctly represent the motion qualitatively.
( a=a = acceleration, v=v = velocity, x=x = dispalcement, t=t = time)
(A)\left(A\right) A particle starts from origin O from rest and moves with a uniform acceleration along the positive x - axis . Identify
(B)\left(B\right) A particle starts from origin O from rest and moves with a uniform acceleration along the positive x - axis . Identify
(C)( C ) A particle starts from origin O from rest and moves with a uniform acceleration along the positive x - axis . Identify
(D)( D ) A particle starts from origin O from rest and moves with a uniform acceleration along the positive x - axis . Identify

Options

  1. A(A),(B),(D)\left(A\right), \left(B\right), ( D )
  2. B(A),(B),(C)\left(A\right), \left(B\right), ( C )
  3. C(B),(C)\left(B\right), ( C )
  4. D(A)( A )

Correct answer

A. (A),(B),(D)\left(A\right), \left(B\right), ( D )

Step-by-step solution

A. Acceleration = constant; av→tav \to t graph will be constant line parallel to time axis. Option (A)\left(A\right) is correct.
B. v=u+atv = u + at ; velocity vs time graph will be straight line passing through origin. Option (B)\left(B\right) is correct.
u=0;u = 0; initially at rest
v=v = at
C. X=12at2X = \dfrac{1}{2}a{t}^{2} (particle was initially at origin) v→tv \to t graph will be parabola passing through origin. Option (D)\left(D\right) is correct.
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