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JEE Main2015PhysicsMotion in One DimensionActual

From the top of a 64 metres high tower, a stone is thrown upwards vertically with the velocity of 48 m / s . The greatest height (in metres) attained by the stone, assuming the value of the gravitational acceleration g = 32 m / s 2 , is:

Options

  1. A112
  2. B88
  3. C128
  4. D100

Correct answer

D. 100

Step-by-step solution

We know that v 2 = u 2 + 2 g s . At greatest height v = 0 u = 48   m / sec g = - 32  m / sec 2 S = 48 × 48 2.32 = 36   m Total distance = 64   m + 36   m = 100   m = 100   m

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