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JEE Main 201511 AprilOnline
Exam
JEE Main
Year
2015
Date
11 April
Mode
Online
Subject
Physics
Chapter
Motion in One Dimension

JEE Main 2015 · 11 April · Online · Physics · Motion in One Dimension

From the top of a 64 metres high tower, a stone is thrown upwards...

From the top of a 6464 metres high tower, a stone is thrown upwards vertically with the velocity of 48m/s.48m / s . The greatest height (in metres) attained by the stone, assuming the value of the gravitational acceleration g=32m/s2g = 32m / {s}^{2}, is:

Options

  1. A112112
  2. B8888
  3. C128128
  4. D100100

Correct answer

D. 100100

Step-by-step solution

We know that v2=u2+2gs.{v}^{2} = {u}^{2} + 2gs .

At greatest height v=0v = 0

u=48m/secu = 48m / sec

g=−32m/sec2g = - 32{m / sec}^{2}

S=48×482.32=36mS = \dfrac{48 \times 48}{2.32} = 36m

Total distance =64m+36m=100m= 64m + 36m = 100m

=100m= 100m

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