A goods train accelerating uniformly on a straight railway track, approaches an electric pole standing on the side of track. Its engine passes the pole with velocity u and the guard's room passes with velocity v . The

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Correct answer: D. ((u^2+v^2)/(2))

Let ' S ' be the distance between two ends ' a ' be the constant acceleration As we know V^2-u^2=2 a S or, a S=(V^2-u^2)/(2) Let V be velocity at mid point. Therefore, V_c^2-u^2=2 a (S)/(2) aligned & V_c^2=u²+a S & V_c^2=u²+(V^2-u^2)/(2) & V_c= (u^2+v^2)/(2) aligned

A goods train accelerating uniformly on a straight railway track,...

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