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JEE Main2011PhysicsMotion in One DimensionActual

An object, moving with a speed of 6.25 ~m / s , is decelerated at a rate given by : dv dt =-2.5 v where v is the instantaneous speed. The time taken by the object, to come to rest, would be:

Options

  1. A2 ~s
  2. B4 ~s
  3. C8 ~s
  4. D1 ~s

Correct answer

A. 2 ~s

Step-by-step solution

d v d t =-2.5 v Integrating the above equation. 2 v =-2.5 t + C at t =0, v =6.25 C =5 at v=0 t= 5 2.5 =2 ~s

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